Question

solve

4 q² +59 + 1 = 0​

Answer 1

Step-by-step explanation:

1 4q²+59+1=0

answer

1. add the number

4q²+59+1=0

4q²+60=0

2. common factor

4q²+60=0

4(q²+15)=0

3. divide both sides of the equation by the same term.

4(q²+15)=0

q²+15=0

Use the quadratic formula

=

−

±

2

−

4

√

2

q=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

2

+

1

5

=

0

q^{2}+15=0

=

1

a={\color{#c92786}{1}}

=

0

b={\color{#e8710a}{0}}

=

1

5

c={\color{#129eaf}{15}}

=

−

0

±

0

2

−

4

⋅

1

⋅

1

5

√

2

1

5

Simplify

Evaluate the exponent

Multiply the numbers

Subtract the numbers

Add zero

Multiply the numbers

=

±

−

6

0

√

2

6

No real solutions because the discriminant is negative

The square root of a negative number is not a real number

= -60

Answer 2

Answer:

The value of q is $\sqrt{-15}$

Step-by-step explanation:

We have been given here the following equation where we have to find the value of the variable x by solving it. We will separate all the variables on the LHS side and constant terms on the RHS side as below:

$4q^{2} + 59 +1 = 0$

⇒ $4q^{2} = - 60$

⇒ $q^{2}$ = -60 ÷ 4

⇒ $q^{2}$ = - 15

⇒ q = $\sqrt{-15}$

Hence the value of q is $\sqrt{-15}$