Question

solve 4 root 3 X square + 5 x minus 2 root 3 is equal to zero by quadratic formula​

Answer 1

Answer:

HERE IS YOUR ANSWER..

Step-by-step explanation:

4√3x^2+5x-2√3=0

4√3x^2+8x-3x-2√3=0

4x(√3x+2)-√3(√3x-2)=0

(4x-√3) (√3x+2)=0

4x-√3=0

4x=√3

x=√3/4

√3x+2=0

√3x=-2

x=-2/√3 ans

HOPE IT HELPS

PLZ MARK AS BRAINLIEST

Answer 2

Answer:

The values of x are $\sqrt{3} /4$ and $-2/\sqrt{3}$.

Step-by-step explanation:

As per the data given in the question,

we need to slove,

$4\sqrt{3}x^{2} +5x-2\sqrt{3} = 0\\4\sqrt{3}x^{2} +8x-3x- 2\sqrt{3} = 0\\4x(\sqrt{3}x +2) -\sqrt{3}(\sqrt{3}x +2)=0\\(\sqrt{3}x +2)(4x-\sqrt{3})=0$

so, by equating both

$\sqrt{3}x +2=0\\x=-2/\sqrt{3}$

Also,

$4x-\sqrt{3} =0\\x=\sqrt{3}/4$

hence, the values of x are $\sqrt{3} /4$ and $-2/\sqrt{3}$.

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