Math, asked by dside0987, 9 months ago

Solve 4+root-32/6 pls ans fast

Answers

Answered by Anonymous
4

Answer:

4 +  \sqrt{ \frac{32}{6} }  =  >  \\  \\  \\  =  > 4 +  \frac{4 \sqrt{2} }{ \sqrt{6} }  \\  \\  \\  =  >  \frac{4 \sqrt{6}  + 4 \sqrt{2} }{ \sqrt{6} }  \\  \\  \\  =  \frac{4( \sqrt{6} +  \sqrt{2)}  }{ \sqrt{6} }  \\  \\  =  >  \frac{4(2.44 + 1.41)}{2.44}  \\  \\  =  >  \frac{4(3.85)}{2.44}  \\  \\  \\  =  >  \frac{15.4}{2.44}  =  6 . 31

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Answered by sara2449
1

Answer:

the question isn't clear..

if it is

 \frac{4 +  \sqrt{32} }{6}

then the answer will be

 \frac{4 + 4 \sqrt{3} }{6}  \\  \frac{2(2 + 2 \sqrt{3)} }{6}  \\  \frac{2 + 2 \sqrt{3} }{3}

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