Question

solve (4(root3+1)+8)​

Answer 1

SOLUTION

TO SOLVE

$\sf{4( \sqrt{3} + 1) + 8}$

EVALUATION

Here the given expression is

$\sf{4( \sqrt{3} + 1) + 8}$

We simplify it as below

First method :

$\sf{4( \sqrt{3} + 1) + 8}$

$\sf{ = 4 \sqrt{3} +4 + 8}$

$\sf{ = 4 \sqrt{3} +12}$

$\sf{ = 12 + 4 \sqrt{3} }$

Second method :

$\sf{4( \sqrt{3} + 1) + 8}$

$\sf{ = 4( \sqrt{3} + 1 + 2)}$

$\sf{ = 4( \sqrt{3} + 3)}$

$\sf{ = 4( 3+ \sqrt{3} )}$

$\sf{ = 12+ 4\sqrt{3} }$

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Answer 2

Step-by-step explanation:

SOLUTION

TO SOLVE

\sf{4( \sqrt{3} + 1) + 8}4(

3

+1)+8

EVALUATION

Here the given expression is

\sf{4( \sqrt{3} + 1) + 8}4(

3

+1)+8

We simplify it as below

First method :

\sf{4( \sqrt{3} + 1) + 8}4(

3

+1)+8

\sf{ = 4 \sqrt{3} +4 + 8}=4

3

+4+8

\sf{ = 4 \sqrt{3} +12}=4

3

+12

\sf{ = 12 + 4 \sqrt{3} }=12+4

3

Second method :

\sf{4( \sqrt{3} + 1) + 8}4(

3

+1)+8

\sf{ = 4( \sqrt{3} + 1 + 2)}=4(

3

+1+2)

\sf{ = 4( \sqrt{3} + 3)}=4(

3

+3)

\sf{ = 4( 3+ \sqrt{3} )}=4(3+

3

)

\sf{ = 12+ 4\sqrt{3} }=12+4

3