Question

solve:4(x+2)-3(2-x)=3(x+4)-2(4-x).
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Answer 1

$\huge\bold\red{Answer}$

$4(x + 2) - 3(2 - x) = 3(x + 4) - 2(4 - x) \\ \\ 4x + 8 - 6 + 3x = 3x + 12 - 8 + 2x \\ \\ 7x + 2 = 5x + 4 \\ \\ 7x - 5x = 4 - 2 \\ \\ 2x = 2 \\ \\ x = \frac{2}{2} \\ \\ x = 1$

Answer 2

★Answer :-

• Value of x is 1 .

★Step-by-step-Explaination :-

$\rm \: 4(x + 2) - 3(2 - x) = 3(x + 4) - 2(4 - x)$

Here , outside brackets numbers are there which we have to multiply it and opening brackets :

$\rm \: \implies 4x + 8 - 6 - x= 3x + 12 - 8 + 2x$

Now bringing X one side and Constant one side :

$\rm \: \implies 4x - x - 3x - 2x= + 12 - 8 - 8 + 6$

Just finding out ,

$\rm \: \implies - 2x= 18 - 1 6$

So , it becomes :

$\rm \: \implies - 2x= - 2$

Taking -2 to R.H.S to divide it with -2

$\rm \: \implies - x= \dfrac{- 2}{2}$

Getting value of x .

$\rm \: \implies - x= - 1$

Now , see x is also negative and 1 is also negative . So,

Let's make it positive .

$\rm \: \implies \bf x= 1$

$\therefore \sf \: Value \: of \: x \: is \: 1$

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