Question

solve 4/x+3y=8 , 6/x-4y=-5 by elimination or subsituition method

Answer 1

Answer:

$\text{The solution is x=2 and y=2}$    

Step-by-step explanation:

Given two equations

$\frac{4}{x}+3y=8,\frac{6}{x}-4y=-5$

we have to solve the above two by elimination or substitution method.

$\text{First we substitute u = }\frac{1}{x}\text{ we get the two equations as}$

$4u+3y=8........(1)$

$6u-4y=-5........(2)$

Multiply (1) eq by 3 and second equation by 2, we get

$12u+9y=24........(3)$

$12u-8y=-10........(4)$

Subtract equation (4) from (3)

$9y-(-8y)=24-(-10)$

$17y=34$

$y=\frac{34}{17}=2$

$4u+3y=8$

$4u+6=8$

$4u=2$

$u=\frac{1}{2}$

$\frac{1}{x}=\frac{1}{2}$

$x=2$

$\text{Hence, the solution is x=2 and y=2}$

Answer 2

Answer:

Step-by-step explanation: