solve 4/x + 5y= 7 and 3/x + 4y= 5
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4/x+5/y=7 .....(1)
3/x+4y=5 ......(2)
4×2–3×(3)
12x+16y–12x–15y=20–21
y=–1
substitute y=–1 in (1) we get
4x+5×–1 =7
4x = 7+5=12
or x = 12/4=3
x=3 y=–1
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