Solve: 4(y+3)/8 =7+ 5y/13
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4y+12/8=7+5y/13
13(4y+12)=8(7+5y)
52y+156=56+40y
52y-40y=56-156
12y= -100
y= -100/12
y= -8.33
Answered by
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Step-by-step explanation:
4(y+3)/8 = 7 + 5y/13
13 × 4 (y + 3) = 8 × (7 + 5y)
52 (y + 3) = 8 (7 + 5y)
52y + 156 = 56 + 40y
52y - 40y = 56 - 156
12y = -100
y = -100/12
y = -25/3
The quotient is non-terminating (8.3333333333.....)
Hope it helps
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