Math, asked by sonu6411, 4 months ago

Solve: 4(y+3)/8 =7+ 5y/13​

Answers

Answered by kalaiyarasim2001
0

4y+12/8=7+5y/13

13(4y+12)=8(7+5y)

52y+156=56+40y

52y-40y=56-156

12y= -100

y= -100/12

y= -8.33

Answered by nightread
0

Step-by-step explanation:

4(y+3)/8 = 7 + 5y/13

13 × 4 (y + 3) = 8 × (7 + 5y)

52 (y + 3) = 8 (7 + 5y)

52y + 156 = 56 + 40y

52y - 40y = 56 - 156

12y = -100

y = -100/12

y = -25/3

The quotient is non-terminating (8.3333333333.....)

Hope it helps

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