Math, asked by schoolt634, 17 days ago

solve: 41x < 100 where x is a natural number..​

Answers

Answered by gugilapuvistnu
0

Answer:

Answer :D

Sol : Option D

Explanation: SI = 10 – 4 = 6 therefore, 6 = (4xRx50)/100 → R = 3 %.

Sol : Option D

Explanation: 210 = (Px7x1)/100x12 → P = 36000

Sol : Option A

Explanation: Interest for 6 years = 640 – 460 = Rs.180

therefore, Interest for 2 years = (180/6)x2 = Rs.60

therefore, 460 will become 460 + 60 = Rs. 520 after 2 years

Sol : Option A

Explanation: R=[100(x-1)]/t % therefore, R = [100(7/4-1)]/3 = 25%

Sol : Option E

Explanation: Interest =37 – 25 = 12 → 12 = (25/100)x16xT → T = 3 years

Sol : Option A

Explanation: = P/4 =(PxRxR)/100 → R2 =25% → R = 5%

Sol : Option D

Explanation: Interest = 66 – 60 = 6 therefore, 6 = 60/100 x R x 4/12 ⇒ R= 30%.

Sol : Option D

Explanation: Interest = 200 ⇒ 200 = (500 x R x 4)/100 ⇒ R = 10 %.

Sol : Option A

Explanation: 2000 = (10,000x10xT)/100

T = 2 years

Sol : Option C

Explanation: Interest at 1st rate for 1 year = 800 x (6x1)/100 = Rs. 48.

Interest for 1 year at 2nd rate = 1200 x (7 x 1)/100 = Rs. 84

therefore, Total interest for 1 year = Rs. 132.

Hence, the required time = 1584/132 = 12 years.

Hope it helped you

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Answered by naziralirawat
0

10041 9292999/927761 972

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