Question

solve. (4² + 6²) ×6
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Answer 1

Answer:

The value of  $(4^{2} +6^{2} )*6$ is $312$.

                   

Step-by-step explanation:

Given : $(4^{2} +6^{2} )*6$

To find : The value of above expression.

Solution :

• The given expression is,  $(4^{2} +6^{2} )*6$
• We know that, square of any number is defined as product of given number with itself.
• To solve the given expression, we have to use BODMAS rule, which means while solving a problem, first solve B-bracket, O-order, D-division, M-multiplication, A-addition and then S-subtraction.

• The given equation is,  $(4^{2} +6^{2} )*6$
•  First solving bracket, we know that

               $4^{2} =16$ and $6^{2} =36$

• ∴  $(4^{2} +6^{2} )*6$ $=(16+36)*6$

                           $= 52*6$

                           $=312$  

• ∴ The value of  $(4^{2} +6^{2} )*6$ is $312$.

                   

Answer 2

• As per the data given in the question, we have to find the value of the expression.

             Given data:- $\left(4^{2}+6^{2}\right) \times 6.$

            To find:-Value of given expression=?

            Solution:-

• To solve the above equation we will follow the BODMAS rule.

• It is the rule used to remember the order of operations to be followed while solving expressions in mathematics.

          where,

                 $\begin{array}{l}\mathrm{B}=\text { brackets } \\\mathrm{O}=\text { order of powers or rules } \\\mathrm{D}=\text { division } \\\mathrm{M}=\text { multiplication } \\\mathrm{A}=\text { addition } \\\mathrm{S}=\text { subtraction }\end{array}$

         Therefore,

              $\left(4^{2}+6^{2}\right) \times 6\\=(16+36)\times6\\=52\times6\\=312.$

        Hence we will get the value $312.$