Question

Solve:
43x + 67y = -24
67x + 43y = 24
please help me in question​

Answer 1

43x+67y=−24

(i)67x+43y=24

(ii)⇒110x+110y=0 [ Adding (i) and (ii) ] 

⇒x+y=0.

(iii)Subtracting

 (ii) from

 (i) we have −24x+24y=−48

⇒−x+y=−2.

(iv)x+y=0 [ From (iii) ] 

⇒2y=−2 [ adding 

(iii) and 

(iv)]

y=−1

From

(iii),x+y=0

⇒x+(−1)=0[∵y=−1]

⇒x=1

and y=−1

hence the solution of the given equations is x=1,y=−1

Answer 2

$\LARGE\underline\mathtt \red{ Answer }$

so, here's the solution begins :

$\rm 43x+67y=-24$

(i) $\rm 67x+43y=24$

LTE 4G, 96

(ii) 110x+110y=0 $\bf{[Adding (i) and (ii)] }$

$\implies$ x+y=0.

(iii) Subtracting (ii) from (i) we have

$\implies$$\rm{-24x+24y=-48}$

$\implies$$\rm{-x+y=-2}$

(iv) x+y=0 [From (iii)] (iii) and (iv)]

y=-1 From Vol 4G 96 LTE

(iii),x+y=0

$\implies$$\rm{x+(-1)=0[*y=-1]}$

$\implies$$\rm{x=1}$ and $\rm y=-1$

hence the solution of the given equations is

$\bf \purple{ x \: = \: 1, \: \: y \: = \: -1 }$