Question

Solve:
43x + 67y = -24
67x + 43y = 24
please help me in question​

Answer 1

$\LARGE\underline\mathtt \red{ Answer }$

so, here's the solution begins :

$\rm 43x+67y=-24$

(i) $\rm 67x+43y=24$

LTE 4G, 96

(ii) 110x+110y=0 $\bf{[Adding (i) and (ii)] }$

$\implies$ x+y=0.

(iii) Subtracting (ii) from (i) we have

$\implies$$\rm{-24x+24y=-48}$

$\implies$$\rm{-x+y=-2}$

(iv) x+y=0 [From (iii)] (iii) and (iv)]

y=-1 From Vol 4G 96 LTE

(iii),x+y=0

$\implies$$\rm{x+(-1)=0[*y=-1]}$

$\implies$$\rm{x=1}$ and $\rm y=-1$

hence the solution of the given equations is

$\bf \purple{ x \: = \: 1, \: \: y \: = \: -1 }$

Answer 2

\LARGE\underline\mathtt \red{ Answer }

Answer

so, here's the solution begins :

\rm 43x+67y=-24 43x+67y=−24

(i) \rm 67x+43y=24 67x+43y=24

LTE 4G, 96

(ii) 110x+110y=0 \bf{[Adding (i) and (ii)] }[Adding(i)and(ii)]

\implies ⟹ x+y=0.

(iii) Subtracting (ii) from (i) we have

\implies ⟹ \rm{-24x+24y=-48}−24x+24y=−48

\implies ⟹ \rm{-x+y=-2}−x+y=−2

(iv) x+y=0 [From (iii)] (iii) and (iv)]

y=-1 From Vol 4G 96 LTE

(iii),x+y=0

\implies ⟹ \rm{x+(-1)=0[*y=-1]}x+(−1)=0[∗y=−1]

\implies ⟹ \rm{x=1}x=1 and \rm y=-1 y=−1

hence the solution of the given equations is

\bf \purple{ x \: = \: 1, \: \: y \: = \: -1 }x=1,y=−1

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