SOLVE :
47x +31y =63
31x +47y=15
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Answered by
1
Answer:
47x + 31y = 63........1
31x + 47y = 15.........2
adding 1 and 2
78x + 78y = 78
x + y = 1..........3
subtracting 1 and 2
16x - 16y = 48
x - y = 3...........4
adding 3 and 4
2x = 5
x = 5/2
putting the value of x in 3
5/3 + y =1
y = 1-5/3
y = -2/3
Answered by
11
Solution :-
47x + 31y = 63 _________(i)
31x + 47y = 15 _______(ii)
According equation (i) and equation (ii)
78x + 78y = 78
=> 78(x + y) = 78
=> x + y = 1 => x = 1 - y _______(iii)
Subtracting equation (ii) from equation (i),
16x - 16y = 48
=> 16(x - y) = 48
=> x - y = 3
=> (1 - y) - y = 3 [from equation (iii)]
=> 1 - y - y = 3
=> - 2y = 3 - 1
=> y = 2/-2 = - 1
Now, Substituting the value of y in equation (iii),
=> x = 1 - (-1) = 1 + 1 = 2
Hence,
x = 2 and y = - 1
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