Question

Solve
49x-57y=172 ; 57x-49y=252​

Answer 1

Answer:

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Answer 2

49x−57y=172(I)

57x−49y=252(II)

Adding (I) and (II)

49x+57x−57y−49y=172+252

⇒106x−106y=424

⇒106x−106y=424⇒x−y=4(III)

⇒106x−106y=424⇒x−y=4(III)Subtracting (II) from (I) we have

⇒106x−106y=424⇒x−y=4(III)Subtracting (II) from (I) we have49x+57x−57y−(−49y)=252−172

⇒106x−106y=424⇒x−y=4(III)Subtracting (II) from (I) we have49x+57x−57y−(−49y)=252−172⇒−8x−8y=−80

⇒106x−106y=424⇒x−y=4(III)Subtracting (II) from (I) we have49x+57x−57y−(−49y)=252−172⇒−8x−8y=−80⇒−x−y=−10

⇒106x−106y=424⇒x−y=4(III)Subtracting (II) from (I) we have49x+57x−57y−(−49y)=252−172⇒−8x−8y=−80⇒−x−y=−10⇒x+y=10(IV)

Subtracting (II) from (I) we have

Subtracting (II) from (I) we have49x+57x−57y−(−49y)=252−172

Subtracting (II) from (I) we have49x+57x−57y−(−49y)=252−172⇒−8x−8y=−80

Subtracting (II) from (I) we have49x+57x−57y−(−49y)=252−172⇒−8x−8y=−80⇒−x−y=−10

Subtracting (II) from (I) we have49x+57x−57y−(−49y)=252−172⇒−8x−8y=−80⇒−x−y=−10⇒x+y=10(IV)

Subtracting (II) from (I) we have49x+57x−57y−(−49y)=252−172⇒−8x−8y=−80⇒−x−y=−10⇒x+y=10(IV)Adding (III) and (IV)

Subtracting (II) from (I) we have49x+57x−57y−(−49y)=252−172⇒−8x−8y=−80⇒−x−y=−10⇒x+y=10(IV)Adding (III) and (IV)x−y=4

Subtracting (II) from (I) we have49x+57x−57y−(−49y)=252−172⇒−8x−8y=−80⇒−x−y=−10⇒x+y=10(IV)Adding (III) and (IV)x−y=4x+y=10

Subtracting (II) from (I) we have49x+57x−57y−(−49y)=252−172⇒−8x−8y=−80⇒−x−y=−10⇒x+y=10(IV)Adding (III) and (IV)x−y=4x+y=10⇒2x=14

Subtracting (II) from (I) we have49x+57x−57y−(−49y)=252−172⇒−8x−8y=−80⇒−x−y=−10⇒x+y=10(IV)Adding (III) and (IV)x−y=4x+y=10⇒2x=14⇒x=7

Subtracting (II) from (I) we have49x+57x−57y−(−49y)=252−172⇒−8x−8y=−80⇒−x−y=−10⇒x+y=10(IV)Adding (III) and (IV)x−y=4x+y=10⇒2x=14⇒x=7Putting the value of x = 7 in (IV) we get

Subtracting (II) from (I) we have49x+57x−57y−(−49y)=252−172⇒−8x−8y=−80⇒−x−y=−10⇒x+y=10(IV)Adding (III) and (IV)x−y=4x+y=10⇒2x=14⇒x=7Putting the value of x = 7 in (IV) we get7+y=10

Subtracting (II) from (I) we have49x+57x−57y−(−49y)=252−172⇒−8x−8y=−80⇒−x−y=−10⇒x+y=10(IV)Adding (III) and (IV)x−y=4x+y=10⇒2x=14⇒x=7Putting the value of x = 7 in (IV) we get7+y=10⇒y=10−7

Subtracting (II) from (I) we have49x+57x−57y−(−49y)=252−172⇒−8x−8y=−80⇒−x−y=−10⇒x+y=10(IV)Adding (III) and (IV)x−y=4x+y=10⇒2x=14⇒x=7Putting the value of x = 7 in (IV) we get7+y=10⇒y=10−7⇒y=3

Subtracting (II) from (I) we have49x+57x−57y−(−49y)=252−172⇒−8x−8y=−80⇒−x−y=−10⇒x+y=10(IV)Adding (III) and (IV)x−y=4x+y=10⇒2x=14⇒x=7Putting the value of x = 7 in (IV) we get7+y=10⇒y=10−7⇒y=3Thus, (x,y)=(7,3)