solve (4a+3)² - (3a-2)²
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(4a+3)²-(3a-2)²
(a+ b)²= a²+ b²+2ab
(a-b)²=a²+b²-2ab
{(4a)²+(3)²+2×4a×3} - {(3a)²+(2)²-2×3a×2}
{16a²+9+24a} - {9a²+4 -12a}
16a²+9+24a-9a²- 4+12a
7a²+36a+5 ANSWER
@GAVYA
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