Question

solve (4a+3)² - (3a-2)²​

Answer 1

(4a+3)²-(3a-2)²

(a+ b)²= a²+ b²+2ab

(a-b)²=a²+b²-2ab

{(4a)²+(3)²+2×4a×3} - {(3a)²+(2)²-2×3a×2}

{16a²+9+24a} - {9a²+4 -12a}

16a²+9+24a-9a²- 4+12a

7a²+36a+5          ANSWER

@GAVYA

Answer 2

Answer:

16a^2+6a+4

Step-by-step explanation:

$(4a + 3) {}^{2} - (3a - 2){}^{2} \\expand \: the \: bracket \: \\ 4a + 3 \times 4a + 3 - 3a - 2 \times 3a - 2 \\ \: group \: like \: terms \\ 16a {}^{2} + 12a - 6a + 4 \: \\ final \: answer \\ 16 {}^{2} + 6a + 4$

Hope it helps thanks ☺️