Question

solve (4a-3) cube by identity( x+y )cube = x cube +y cube +3xy(x+y)​

Answer 1

Answer:

[4a + (-3)] ^3 = 4a^3 + (-3)^3 + 3(4a)(-3)[4a+(-3)]

= 64a^3 - 27^3 - 36a ( 4a-3)

= 64a^3 - 27^3 - 144a^2 + 108a

I hope that is your answer

Mark this as brainliest plz