Math, asked by Madhur00193, 6 months ago

solve (4a-5) (a²+b²-2ab) by using column method​

Answers

Answered by hamzashahbaz878
2

Answer:

-1-1+2a^2b^2

Step-by-step explanation:

= 4a [a^2+b^2-2ab]

=4a^3+4ab^3-8a^2b

= -5a[a^2+b^2-2ab]

=-5a^3-5ab^3+10a^2b

=4a^3-5a^3+4ab^3-5ab^3-8a^2b+10a^2b

= -1-1+2a^2b^2

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