solve (4a-5) (a²+b²-2ab) by using column method
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Answer:
-1-1+2a^2b^2
Step-by-step explanation:
= 4a [a^2+b^2-2ab]
=4a^3+4ab^3-8a^2b
= -5a[a^2+b^2-2ab]
=-5a^3-5ab^3+10a^2b
=4a^3-5a^3+4ab^3-5ab^3-8a^2b+10a^2b
= -1-1+2a^2b^2
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