solve;4a+8=0‚ a=2‚-2‚3.
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Answered by
0
Answer:
The first term is, a2 its coefficient is 1 .
The middle term is, +4a its coefficient is 4 .
The last term, "the constant", is +8
Step-1 : Multiply the coefficient of the first term by the constant 1 • 8 = 8
Step-2 : Find two factors of 8 whose sum equals the coefficient of the middle term, which is 4 .
-8 + -1 = -9
-4 + -2 = -6
-2 + -4 = -6
-1 + -8 = -9
1 + 8 = 9
2 + 4 = 6
4 + 2 = 6
8 + 1 = 9
Observation : No two such factors can be found !!
Answered by
0
Answer:
4 a+8=0. (a=2-2+3)
Step-by-step explanation:
4 (2-2+3)+8=0 8-8+12+8=0 solved
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