Question

solve 4a-bi=8+2i find the solution of this question​

Answer 1

Step-by-step explanation:

I think here in this equation 4a-bi=8+2i=0 will come so from this u can get values

Answer 2

The solution of the given question is a = 2 and b = -2.

Given:

4a-bi=8+2i

To Find:

The solution of the given equation.

Solution:

We have been given the equation

4a-bi = 8+2i.

We are asked to find the solution of the given equation, i.e. we have to find the values of 'a' and 'b'.

A complex number has the form x+iy, where 'x' is the real part and 'y' is the imaginary part.

We will be comparing the real and imaginary parts of the expressions on both sides to find the values of 'a' and 'b'.

On the LHS, we have:

4a-bi = 4(a) + (-b)i.

On the RHS, we have:

8+2i = 4(2) + (2)i.

Hence, the given equation becomes:

4(a) + (-b)i = 4(2) + (2)i.

In comparing the real and the imaginary parts, we have:

4(a) = 4(2) ⇒ a = 2.

(-b)i = (2)i ⇒ -b = 2 or b = -2.

∴ The values of a and b are 2 and -2 respectively.

Hence, the solution of the given question is a = 2 and b = -2.

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