Question

solve (4a2-9)(4a2-6a+9)(4a2+6a+9) by formula​

Answer 1

4a²-6a+9= (2a)² - 2 *2*3 a +3² =(2a -3)²

4a²+6a+9= (2a+3)²

4a²-9= (2a)²-3² =(2a+3)(2a-3)

from the expression, it can be expressed as

(2a+3)³ (2a-3)³

Answer 2

$(4a^2-9)(4a^2-6a+9)(4a^2+6a+9)=(2a-3)^3(2a+3)^3$

Step-by-step explanation:

Given : Expression $(4a^2-9)(4a^2-6a+9)(4a^2+6a+9)$

To find : Solve the expression by formula ?

Solution :

Using algebraic identity,

$a^2\pm 2ab+b^2=(a\pm b)^2$

$a^2-b^2=(a+b)(a-b)$

We can write the expression as,

$=((2a)^2-(3)^2)((2a)^2-2\cdot 3\cdot 2a+(3)^2)((2a)^2+2\cdot 3\cdot 2a+(3)^2)$

$=(2a+3)(2a-3)(2a-3)^2(2a+3)^2$

$=(2a-3)^3(2a+3)^3$

Therefore, $(4a^2-9)(4a^2-6a+9)(4a^2+6a+9)=(2a-3)^3(2a+3)^3$

#Learn more

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