Question

Solve 4root6x2-13x-2root6=0 by factorisation method.

Answer 1

$4 \sqrt{6} {x}^{2} - 13x - 2 \sqrt{6} = 0$
$4 \sqrt{6} {x}^{2} - 16x + 3x - 2 \sqrt{6} = 0$
$4x( \sqrt{6} x - 4) + \frac{ \sqrt{6} }{2} ( \sqrt{6} x - 4) = 0$
$( \sqrt{6} x - 4)(4x + \frac{ \sqrt{6} }{2} ) = 0$
$\sqrt{6} x - 4 = 0 \: or \: 4x + \frac{ \sqrt{6} }{2} = 0$
$x = \frac{4}{ \sqrt{6} } \: or \: x = - \frac{ \sqrt{6} }{8}$
$x = \frac{2 \sqrt{6} }{3} \: or \: x = - \frac{ \sqrt{6} }{8}$