solve: 4tan^2x - 2sec^2x +1 =0 ,x belongs to [0,20]
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answer.
X=-4
explanation.
16.4^(x+2)-16.2^(x+1)+1=
=16^(2) . 4^(x)-2.16.2^(x) +1=
=16^2.(2^x)^2- 32.2^x +1=0
making y=2^x
16^2 y^2 -32y+1=0 solving for y we have
y=1/16=2^x =2^-4 then x= -4
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