Question

Solve 4th one okkk plzzzz

Answer 1

Answer:

In triangle SQR,

65° = 25° + angle QSR (one ext. angle = 2 internal opp. angles)

so, angle QSR = 65° - 25° = 40°

Now, Angle PSR = 90°

And, angle PSR = y + 40°

therefore,

y + 40° = 90°

y = 90° - 40° = 50°

Now, In triangle PQS,

Angle SPQ + angle PQS + angle QSP = 180°

90° + x + y = 180°

x + y = 180° - 90° = 90°

or, x = 90° - y = 90° - 50° = 40°

Therefore,

x = 40° and y = 50°

Answer 2

Answer:

The value of x is 40° whereas the value of y is 50°.

Step-by-step explanation:

Given

PQ || SR

<SQR = 25°

<QRT = 65°

<SPQ = 90°

To find, x and y.

So,

<PQR = <QRT (corresponding angle theorem)

<PQS + <SQR = <QRT

x + 25 = 65

x = 40

Now, in triangle PQS,

<SPQ = 90°

<PQS = 40°

<PSQ = (to find)

WKT, triangle has a measure of 180°.

So,

<SPQ + <PQS + <PSQ = 180

90 + 40 + y = 180

y = 180 - 130

y = 50