Question

Solve 4th sum it is the sum from chapter- Quadratic equations
Plz solve fast in a copy nd snd me attachment

Answer 1

$GIven : \frac{a}{ax-1} + \frac{b}{bx-1} = a + b$

$= \ \textgreater \ \frac{a}{ax - 1} - b + \frac{b}{bx - 1} - a = 0$

$= \ \textgreater \ \frac{a - abx + b}{ax - 1} = \frac{abx - a - b}{bx - 1}$

$= \ \textgreater \ (a - abx + b)( \frac{1}{ax - 1} + \frac{1}{bx - 1} ) = 0$

$= \ \textgreater \ (a - abx + b)(ax -1 + bx - 1) = 0$

$= \ \textgreater \ (a - abx + b)(ax + bx - 2) = 0$

(1)

[tex]= \ \textgreater \ a - abx + b = 0 [/tex]

$= \ \textgreater \ abx = a + b$

$x = \frac{a + b}{2}$


(2)

$= \ \textgreater \ ax + bx - 2 = 0$

$= \ \textgreater \ (a + b)x = 2$

$= \ \textgreater \ x = \frac{2}{a+b}$



Hope this helps!

Answer 2

Hi,

Please see the attached file!



Thanks