Question

Solve 4x^2- 3x -1 = 0​

Answer 1

Answer:x=1 or x=1/4

Step-by-step explanation:

1). 4x²-3x-1=0. 2). 4x²-4x+x-1=0. 3) 4x(x-1)-1(x-1) 4) (4x-1) (x-1)

so x=1 or x=1/4

Answer 2

4x² - 3x -1 =0

$= > \: 4( {x}^{2} - \frac{3}{4} x) = 1 \\ = > \: {x}^{2} - \frac{3}{4}x = \frac{1}{4} \\ = > \: {x}^{2} - \frac{3}{4} x + ( \frac{3}{8} ) {}^{2} = \frac{1}{4} + ( \frac{3}{8} ) {}^{2} \\ = > \: (x - \frac{3}{8}) {}^{2} = \frac{1}{4} + \frac{9}{64} = \frac{25}{64} = (\frac{5}{8} ) {}^{2} \\ = > \: x - \frac{3}{8} = + - ( \frac{5}{8}) \\ \\ x = \frac{3}{8} + - (\frac{5}{8} ) \\ = > \: x = \frac{3}{8} + \frac{5}{8} = 1......(taking \: + ) \\ \\ = > x = \frac{3}{8} - \frac{5}{8} = - \frac {1}{4} .........(taking \: - )$

Hence, the solution set of given equation is

$\boxed{ \red{1 \:</strong><strong>,</strong><strong> - \frac{1}{4} }}$