Question

solve 4x^2 -4mx + (m^2-n^2) = 0 to get the value of x​

Answer 1

Answer:

(m+n)/ 2 and (m-n)/2

Step-by-step explanation:

By comparing with Ax² + Bx + C for Equation 4x²-4mx +(m²-n²).

A= 4, B= -4m & C =(m²-n²)

Using quadratic formula, -b +- Root( b²-4ac) / 2a

x =  +4m +- Root [16m² -4*4(m²-n²) ]  / 2* 4

x = 4m +- Root [16m²-16m² +16n²] /8

x = 4m +- Root [16n²] /8

x = 4m +-4n  / 8

x = 4[m+-n]/ 8

x = (m+-n)/2

Answer 2

Answer:

please check the attached file

Step-by-step explanation:

Hopefully it helps