solve 4x^2-5x+1=0 by quadratic formula
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Answer:
a = 4 , b = - 5 , c = = 1
Step-by-step explanation:
D = b² - 4ac
( - 5 )² - 4 × 4 × 1
25 - 16
9
√D = √9
√D = 3
α = - b + √D
2a
5 + 3
2× 4
8 / 8
1
β = - b -√D
2a
5 - 3
2×4
2 / 8
1 / 4
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