Question

solve : (4x+3/2x-1)+(3x-8/x-2)=5​

Answer 1

Answer:

(4x+3/2x-1)+(3x-8/x-2)=5

(4x+3)(x-2)+(3x-8)(2x-1)/(2x-1)(x-2)=5

4x(x-2)+3(x-2)+3x(2x-1)-8(2x-1)/2/2x(x-2)-1(x-2)=5

4x(x-2)+3(x-2)+3x(2x-1)-8(2x-1)/2/2x(x-2)-1(x-2)=54x^2-8x+3x-6+6x^2-3x-16x+8/2x^2-4x-1x+2=5

4x(x-2)+3(x-2)+3x(2x-1)-8(2x-1)/2/2x(x-2)-1(x-2)=54x^2-8x+3x-6+6x^2-3x-16x+8/2x^2-4x-1x+2=54x^2+6x^2-8x+3x-3x-16x-6+8/2x^2-5x+2=5

10x^2-24x+2/2x^2-5x+2=5

10x^2-24x+2=5(2x^2-5x+2)

10x^2-24x+2=10x^2-25x+10

-24x+25x=10-2

x=8

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