Math, asked by nikhilroyn1357, 7 months ago

Solve (4x+3)(3x+2)(x+1)(12x+5)-6 =0

Answers

Answered by mad210203
2

Given:

Given expression is, (4x+3)(3x+2)(x+1)(12x+5)-6=0.

To find:

We need to simplify the given expression.

Solution:

Consider the given expression,

\Rightarrow (4x+3)(3x+2)(x+1)(12x+5)-6=0

We need to simplify the above expression. To simplify, follow the below steps.

First multiply the first two terms, we get

\Rightarrow (12x^2+8x+9x+6)(x+1)(12x+5)-6=0

Simplifying the above expression, we get

\Rightarrow (12x^2+17x+6)(x+1)(12x+5)-6=0

Now multiply the last two terms, we get

\Rightarrow (12x^2+17x+6)(12x^2+5x+12x+5)-6=0

Simplifying the above expression, we get

\Rightarrow (12x^2+17x+6)(12x^2+17x+5)-6=0

Now multiply the two terms, we get

\Rightarrow 144x^4+204x^3+60x^2+204x^3+289x^2+85x+72x^2+102x+30-6=0

Adding similar terms and simplifying it,

\Rightarrow 144x^4+408x^3+421x^2+187x+24=0

The above expression cannot be simplified further.

Therefore, after simplification, the value of given expression is:

144x^4+408x^3+421x^2+187x+24=0.

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