Question

solve
4x-3y=11
6x+7y=5
find the answer ​

Answer 1

Answer:

x=2 and y = -1

Step-by-step explanation:

$4x-3y = 11\\x = \frac{11+3y}{2} \\\frac{3}{2} \times (11+3y) + 7y = 5\\\frac{33}{2}+\frac{9y}{2}+7y =5\\\frac{23y}{2}= \frac{10-33}{2}\\y = -1\\x = \frac{11+3\times -1}{2} \\x = 2$

answered by gauthmath

Answer 2

★ Solution :-

$\sf \leadsto 4x - 3y = 11 \: - - - (i)$

$\sf \leadsto 6x + 7y = 5 \: - - - (ii)$

Now, by first equation,

$\sf \leadsto 4x - 3y = 11$

$\sf \leadsto 4x = 11 + 3y$

$\sf \leadsto x = \dfrac{11 + 3y}{4}$

Now, we can find original value of y.

$\sf \leadsto 6x + 7y = 5$

$\sf \leadsto 6 \bigg( \dfrac{11 + 3y}{4} \bigg) + 7y = 5$

$\sf \leadsto \dfrac{66 + 18y}{4} + 7y = 5$

$\sf \leadsto \dfrac{66 + 18y + 28y}{4} = 5$

$\sf \leadsto \dfrac{66 + 46y}{4} = 5$

$\sf \leadsto 66 + 46y = 5(4)$

$\sf \leadsto 66 + 46y = 20$

$\sf \leadsto 46y = 20 - 66$

$\sf \leadsto 46y = - 46$

$\sf \leadsto y = \dfrac{ - 46}{46}$

$\sf \leadsto y = - 1$

Now, we can find original value of x.

$\sf \leadsto 4x - 3y = 11$

$\sf \leadsto 4x - 3( - 1) = 11$

$\sf \leadsto 4x - ( - 3) = 11$

$\sf \leadsto 4x + 3 = 11$

$\sf \leadsto 4x = 11 - 3$

$\sf \leadsto 4x = 8$

$\sf \leadsto x = \dfrac{8}{4}$

$\sf \leadsto x = 2$

Therefore, the values of x and y are 2 and -1 respectively.