Math, asked by copynewmovies, 9 months ago

solve ; 4x-3y=14 and 7x+8y=51

Answers

Answered by 2435
3

Answer:

Step-by-step explanation:

4x-3y=14

Take 4x=14,-3y=14

x=14/4,y=14/-3

x=7/2,y=-4 2/3

Answered by Yugesh97
1

Answer:

Given; 4x-3y=14 and 7x+8y=51

By elimination method;

4x-3y=14-----;-(equation 1)×7

7x+8y=51-----(equation 2)×4

Then the equations are

28x-21y=98

28x+32y=204

(-). (-). (-)

-----------------------

0-53y=-106

y=-106/-53

y=106/53

y=2

Now substitute y in equation (1)

4x-3y=14

4x-3(2) = 14

4x-6=14

4x=14+6

4x=20

x=20/4

x=5

Therefore x and y are 5 and 2 respectively.

Check:

4x-3y=14. and 7x+8y=51

4(5)-3(2)=14. and 7(5)+8(2)=51

20-6=14. and 35+16=51

14=14. and 51=51

Hope this helps you

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