Math, asked by kunalmanger2, 10 hours ago

solve:4x-3y=16;6x+5y=62​

Answers

Answered by sg693363
1

Answer:

x = 7

y = 4

Step-by-step explanation:

(4x - 3y = 16) × 5 ------ (i)

20x - 15y = 80 ------ (ii)

(6x + 5y = 62) × 3  ------- (iii)

18x + 15y = 186 ------- (iv)

Using Elimination method,

Add (ii) and (iv)

20x - 15y + 18x + 15y = 80 + 186

38x = 266

x=\frac{266}{38} \\\\x=7

20x - 15y = 80

20(7) - 15y = 80

140 - 15y = 80

15y = 140 - 80

15y = 60

y=\frac{60}{15}

y=4

Answered by mohdzaki12mz
0

ANSWER

In this case, the coefficient of x are 4 and 6, thinking of the common multiple of the 4 and 6 comes out to be 12, hence multiplying 4x – 3y = 16 by 3 and 6x + 5y = 62 by 2 makes the coefficient of x as 12 and then subtracting both the equations to eliminate x.

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