Question

Solve 4x+3y=5 and -x+2y=7 by elimination method

Answer 1

$Heya$‼


$Given\:equations :-$
$4x + 3y = 5$ ...{1}
$-x + 2y = 7$ ...{2}


Multiplying {1} by 2 and {2} by 3 ,
8x + 6y = 10 ...a
–3x+6y = 21 ...b


Subtracting a from b :

$-3x+6y = 21$
$8x + 6y = 10$
__________
$-11x = 11$

$x=\frac{11}{-11}$

$x=-1$


Substituting the value of x in {2} ,

$-(-1) + 2y = 7$

$1+2y=7$

$2y=7-1$

$2y=6$

$y=\frac{6}{2}$

$y=3$


Hence, the values of x and y are –1 and 3 respectively.

Answer 2

Answer:

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