Question

solve 4x-3y-6=0 and 5x+2y-19=0 by elimination

Answer 1

Answer:

The two equations are:

4x-3y-6=0

5x+2y-19=0

Multiplying the first equation with 5 and the second one by 4, we get,

5(4x-3y-6=0)

=20x-15y-30=0

4(5x+2y-19=0)

=20x+8y-76=0

Solving the equations,

20x-15y-30=0

20x+8y-76=0

- - + -

___________

-23y+46=0

23y=46

y=46/23

=2

Now, 4x-3y-6=0

4x-3(2)-6=0

=4x-6-6=0

=4x-12=0

=x=12/4

=3

Answer 2

Answer

• x = 3
• y = 2

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