Question

solve 4x-3y=8 6x-y=23/3 by substitution method

Answer 1

Answer:

The answer is

$x \: = 10 \div 4$

Step-by-step explanation:

$4x - 3y = 8$

$4x = 8 + 3y$

$x = (8 + 3y) \div 4$

Let this be the first equation

The other equation is-

$6x - y = 23 \div 3$

Putting the value of 'x' from first equation

$6((8 + 3y) \div 4) - y = 23 \div 3$

$3((8 + 3y) \div 2) - y = 23 \div 3$

$((24 + 9y) \div 4) - y = 23 \div 3$

$6 + (9y \div 4) - y = 23 \div 3$

$5y \div 4 = (23 \div 3) - 6$

$5y \div 4 = 5 \div 6$

$y \div 2 = 1 \div 3$

$y = 2 \div 3$

Let this be the second equation

Put its value in the first equation and you will get

x = 10/4