Question

solve (4x square-3x+7)-(xsquare+ 8x-5)



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Answer 1

Answer:

Step-by-step explanation:

Simplifying

(4x2 + 3x + 7)(8x + -5) = 0

Reorder the terms:

(7 + 3x + 4x2)(8x + -5) = 0

Reorder the terms:

(7 + 3x + 4x2)(-5 + 8x) = 0

Multiply (7 + 3x + 4x2) * (-5 + 8x)

(7(-5 + 8x) + 3x * (-5 + 8x) + 4x2 * (-5 + 8x)) = 0

((-5 * 7 + 8x * 7) + 3x * (-5 + 8x) + 4x2 * (-5 + 8x)) = 0

((-35 + 56x) + 3x * (-5 + 8x) + 4x2 * (-5 + 8x)) = 0

(-35 + 56x + (-5 * 3x + 8x * 3x) + 4x2 * (-5 + 8x)) = 0

(-35 + 56x + (-15x + 24x2) + 4x2 * (-5 + 8x)) = 0

(-35 + 56x + -15x + 24x2 + (-5 * 4x2 + 8x * 4x2)) = 0

(-35 + 56x + -15x + 24x2 + (-20x2 + 32x3)) = 0

Combine like terms: 56x + -15x = 41x

(-35 + 41x + 24x2 + -20x2 + 32x3) = 0

Combine like terms: 24x2 + -20x2 = 4x2

(-35 + 41x + 4x2 + 32x3) = 0

Solving

-35 + 41x + 4x2 + 32x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.