solve 4x-y=7;3x+4y=9 with substitution method in simultaneous equation
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- Equation, 4x - y = 7 --------(1)
- 3x + 4y = 9 ----------(2)
- Value of x & y ,by substitution Method
By, Equation (1)
➠ y = 4x - 7 -----------------(3)
Keep Value of y in equ(2)
➠ 3x + 4 * (4x - 7) = 9
➠ 3x + 16x - 28 = 9
➠ 19x = 9 + 28
➠ 19x = 37
➠ x = 37/19
Now, Keep Value of x in equ(3)
➠ y = 4 * 37/19 - 7
➠ y = (148 - 133)/19
➠ y = 15/19
- Value of x = 37/19
- Value of y = 15/19
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Keep Value of x & y in equ(1)
➠ 4* 37/19 -15/19 = 7
➠ (148 - 15)/19 = 7
➠ 133/19 = 7
➠ 7 = 7
L.H.S. = R.H.S.
That's proved
__________________
Answered by
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Equation, 4x - y = 7 --------(1)
3x + 4y = 9 ----------(2)
Find
Value of x & y ,by substitution Method
Explanation
By, Equation (1)
➠ y = 4x - 7 -----------------(3)
Keep Value of y in equ(2)
➠ 3x + 4 * (4x - 7) = 9
➠ 3x + 16x - 28 = 9
➠ 19x = 9 + 28
➠ 19x = 37
➠ x = 37/19
Now, Keep Value of x in equ(3)
➠ y = 4 * 37/19 - 7
➠ y = (148 - 133)/19
➠ y = 15/19
Hence
Value of x = 37/19
Value of y = 15/19
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