Question

Solve 4x²-2(a²+b²)x+a²b² =0​

Answer 1

Answer:

(2x-a^2)(2x-b^2)

Step-by-step explanation:

using identity

(x+a)(x+b)=x^2+(a+b)x+ab

put X as 2x ((2x)^2)= 4x^2

a as -a^2 and b as -b^2

we get

(2x-a^2)(2x-b^2)

=2x^2 + (-a^2-b^2)2x +(-a^2)(-b^2)

4x^2 + -(a^2+b^2)2x +a^2b^2

Answer 2

OK SO YOUR ANSWER IS ABOVE MY ANSWER