Question

solve 4x²-2(a²+b²)x+a²b²=0 ​

Answer 1

Step-by-step explanation:

4x2 - 2(a2+b2)x + a2b2 = 0

4x2 - 2a2x - 2b2x + a2b2 = 0

2x(2x - a2) - b2(2x - a2) = 0

(2x - a2)(2x - b2) = 0

either 2x - a2 = 0

x = a^2/2

or

2x - b2 = 0

x = b^2/2

Answer 2

Step-by-step explanation:

$( - b + - \sqrt{ {b}^{2} - 4ac } ) \div 2a$

a=4; b= 2(a2+b2); c= a2b2

using the above formula, we get

x= a2/2

x=b2/2