Solve 4x² - 2(a² + b²)x + a²b² = 0
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Step-by-step explanation:
Answer:
x =\frac{a^{2}}{2}\:Or\:x=\frac{b^{2}}{2}x=
2
a
2
Orx=
2
b
2
Step-by-step explanation:
Given quadratic equation:
4x²-2(a²+b²)x+a²b²=0
Splitting the middle term, we get
=> 4x²-2a²x-2b²x+a²b²=0
=> 2x(2x-a²)-b²(2x-a²)=0
=> (2x-a²)(2x-b²)=0
=> 2x-a² = 0 Or 2x-b² = 0
=> 2x = a² Or 2x = b²
\implies x =\frac{a^{2}}{2}\:Or\:x=\frac{b^{2}}{2}⟹x=
2
a
2
Orx=
2
b
2
Therefore,
x =\frac{a^{2}}{2}\:Or\:x=\frac{b^{2}}{2}x=
2
a
2
Orx=
2
b
2
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