Solve : 4x2-5x-6 = 0.
9.
और y में एक संबंध ज्ञात कीजिए, ताकि बिन्दु ( x, y) बिन्दुओं ( 6, 1 ) तथा ( 3, 5 ) से
समदूरस्थ हो।
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★ The value of x is -3/4 ,2.
Given quadratic equation is :-
=> 4x² - 5x - 6 = 0.
=> 4x² - 8x + 3x - 6 = 0.
=> 4x( x - 2 ) + 3( x - 2 ) = 0.
=> ( 4x + 3 ) ( x - 2 ) = 0.
=> x = -3/4 , 2.
Hence the value of x is -3/4 , 2.
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