Math, asked by Ankita4040, 1 month ago

solve 4y-3x+16=0; 2x-3y=0 by substitution , elimination, and cross multiplication method.
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Answers

Answered by mahimaverma2005
1

Answer:

The value of x = 48, and y= 32.

Step-by-step explanation:

-3x + 4y = -16

2x - 3y = 0

using elimination method

multiply by 3 in equation 1 and 4 by in 2

-9x+ 12y = -48

8x - 12y= 0

=[ x= 48]answer.

again put the value of x in equation 2.

2x- 3y = 0

2× 48- 3y = 0

96 - 3y = 0

3y = 96

[ y = 32 ] answer.

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