solve 4y-3x+16=0; 2x-3y=0 by substitution , elimination, and cross multiplication method.
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Step-by-step explanation:
4x - 3y+16= 0 --- (1)
2x - 3y = 0 ---(2)
From equation 2:
y = -2x/3
Substitute y = -2x/3 in equation 1:
4x - 3y+16= 0
4x - 3(-2x/3) + 16 = 0
4x - (3 - 2x/3) + 16 = 0
4x + 2x + 16 = 0
By splitting the middle term 2x
You get an answer
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