solve 4y (3y^3+5y-7)+2 (y^2-4y^2+7)
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12y^4+14y^2-28y+14
Step-by-step explanation:
4y (3y^3+5y-7)+2 (y^2-4y^2+7)
=12y^4+20y^2-28y+2y^2-8y^2+14
=12y^4+14y^2-28y+14
I hope it helps
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