Solve:
4y(3y + 5y-7)+2(y³-4y²+7)
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Answered by
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Answer:
The answer is 2y³+24y²-28y+14
Step-by-step explanation:
4y(8y-7)+2(y³-4y²+7)
32y²-28y+2y³-8y²+14
2y³+32y²-8y²-28y+14
2y³+24y²-28y+14
Answered by
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=4y(3y + 5y-7)+2(y³-4y²+7)
=4y×3y+4y×5y+4y×(-7)+2×y³+2×(-4y²)+2×7
=12y²+20y²-28y+2y³-8y²+14
=12y²+20y²-8y²-28y+2y³+14
=24y²-28y+2y³+14
If we arrange 24y²-28y+2y³+14 in standard form then .
=24y²-28y+2y³+14
=2y³+24y²-28y+14.
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