Question

solve: 4z square -24z +136 = 0

Answer 1

Given: 4z² - 24z + 136 =0

This is simplified as 4(z²-6z+34) = 0

⇒ z²-6z+34 = 0

⇒ Using formula x= [-b±√(b²-4ac)]/(2a) for an equatiion ax²+bx+c=0

here a=1;b=-6,c=34

so z = [-(-6)±√(6²-4*1*34)]/(2*1)

      = [6±√(-100)]/2

      =3±5√(-1)

So z = 3±5*i is a complex number, where i =√(-1) is an imaginary number