Question

Solve: 5-(2x-1)(x-1)=(1-x)(2x-2)

fast​

Answer 1

$\bf \huge \orange{ \underline{Answer : }}$

$\sf \implies \: 5 - (2x - 1)(x - 1) = (1 - x)(2x - 2)$

$\sf \implies \:5 - 2x + 1(x - 1) = 1(2x - 2) - x(2x - 2)$

$\sf \implies \:5x - 2 {x}^{2} + x - 5 + 2x - 1 = 2x - 2 - 2 {x}^{2} + 2x$

$\sf \implies \:8x - 2 {x}^{2} - 7 = 4x - 2 {x}^{2} - 2$

$\sf \implies \:8x \: \: \cancel{ - 2 {x}^{2} } \: - 7 - 4x \: \cancel{ + 2 {x}^{2} } + 2 = 0$

$\sf \implies \:8x - 7 - 4x + 2 = 0$

$\sf \implies \:4x - 5 = 0$

$\sf \implies \:4x = 5$

$\sf \implies \:x = \frac{5}{4}$

$\huge{ \red \bigstar} \purple{\boxed{ \mathfrak{ \pink{x = \frac{5}{4} }}}}$

Answer 2

Answer:

⟹5x−2x2+x−5+2x−1=2x−2−2x2+2x

\sf \implies \:8x - 2 {x}^{2} - 7 = 4x - 2 {x}^{2} - 2⟹8x−2x2−7=4x−2x2−2

\sf \implies \:8x \: \: \cancel{ - 2 {x}^{2} } \: - 7 - 4x \: \cancel{ + 2 {x}^{2} } + 2 = 0⟹8x−2x2−7−4x+2x2+2=0

\sf \implies \:8x - 7 - 4x + 2 = 0⟹8x−7−4x+2=0

\sf \implies \:4x - 5 = 0⟹4x−5=0

\sf \implies \:4x = 5⟹4x=5

\begin{gathered} \sf \implies \:x = \frac{5}{4} \\ \end{gathered}⟹x=45

\huge{ \red \bigstar} \purple{\boxed{ \mathfrak{ \pink{x = \frac{5}{4} }}}}★x=45