Question

solve : 5/3x+1+3/3x-1=8/3x ​

Answer 1

Answer:

LHS=RHS

Step-by-step explanation:

let's solve LHS

5/3x+1+3/3x-1

Taking 3 as LCM

(5x+3+3x-3)/3

=> LHS=8x/3

Here LHS is equal to RHS

Answer 2

Answer:

The value of $x$ is $\dfrac{4}{3}$  .

Step-by-step explanation:

Given that,

$\dfrac{5}{3x+1}+ \dfrac{3}{3x-1}=\dfrac{8}{3x}$

First, we shall cross multiply the left-hand side.

$\dfrac{5(3x-1)+3(3x+1)}{(3x+1)(3x-1)} =\dfrac{8}{3x}$

On expanding the numerator and denominator on the left-hand side of the above equation, we get,

$\dfrac{15x-5+9x+3}{(9x^2-3x+3x-1)} =\dfrac{8}{3x}\\\\\dfrac{24x-2}{(9x^2-1)} =\dfrac{8}{3x}$

Rewriting the equation,

$(24x-2)3x=8(9x^2-1)\\\\72x^2-6x=72x^2-8\\\\-6x=-8\\\\x=\dfrac{8}{6}= \dfrac{4}{3}$