Math, asked by nimmiaapa, 5 months ago

solve 5(5t+6) - 2(t - 3) = t+14​

Answers

Answered by jainbhavna400
2

Answer:

5

(

5

+

6

)

2

(

3

)

=

+

1

4

5(5t+6)-2(t-3)=t+14

5(5t+6)−2(t−3)=t+14

Solve

1

Distribute

5

(

5

+

6

)

2

(

3

)

=

+

1

4

{\color{#c92786}{5(5t+6)}}-2(t-3)=t+14

5(5t+6)−2(t−3)=t+14

2

5

+

3

0

2

(

3

)

=

+

1

4

{\color{#c92786}{25t+30}}-2(t-3)=t+14

25t+30−2(t−3)=t+14

2

Distribute

again

2

5

+

3

0

2

(

3

)

=

+

1

4

25t+30{\color{#c92786}{-2(t-3)}}=t+14

25t+30−2(t−3)=t+14

2

5

+

3

0

2

+

6

=

+

1

4

25t+30{\color{#c92786}{-2t+6}}=t+14

25t+30−2t+6=t+14

3

Add the numbers

2

5

+

3

0

2

+

6

=

+

1

4

25t+{\color{#c92786}{30}}-2t+{\color{#c92786}{6}}=t+14

25t+30−2t+6=t+14

2

5

+

3

6

2

=

+

1

4

25t+{\color{#c92786}{36}}-2t=t+14

25t+36−2t=t+14

4

Combine like terms

2

5

+

3

6

2

=

+

1

4

{\color{#c92786}{25t}}+36{\color{#c92786}{-2t}}=t+14

25t+36−2t=t+14

2

3

+

3

6

=

+

1

4

{\color{#c92786}{23t}}+36=t+14

23t+36=t+14

5

Subtract

3

6

36

36

from both sides of the equation

2

3

+

3

6

=

+

1

4

23t+36=t+14

23t+36=t+14

2

3

+

3

6

3

6

=

+

1

4

3

6

23t+36{\color{#c92786}{-36}}=t+14{\color{#c92786}{-36}}

23t+36−36=t+14−36

6

Simplify

Subtract the numbers

Subtract the numbers

again

2

3

=

2

2

23t=t-22

23t=t−22

7

Subtract

t

t

from both sides of the equation

2

3

=

2

2

23t=t-22

23t=t−22

2

3

=

2

2

23t{\color{#c92786}{-t}}=t-22{\color{#c92786}{-t}}

23t−t=t−22−t

8

Simplify

Combine like terms

Combine like terms

again

2

2

=

2

2

22t=-22

22t=−22

9

Divide both sides of the equation by the same term

2

2

=

2

2

22t=-22

22t=−22

2

2

2

2

=

2

2

2

2

\frac{22t}{{\color{#c92786}{22}}}=\frac{-22}{{\color{#c92786}{22}}}

2222t=22−22

10

Simplify

Cancel terms that are in both the numerator and denominator

Divide the numbers

=

1

Answered by kandulachikki
0

Step-by-step explanation:

5(5t+6) -2(t-3)=t+14

25t+6-2t+3=t+14

25t-2t+6+6=t+14

23t+12=t+14

23t-t=14-12

22t=2

11t=1

11t-1=0

11t=0

t=0

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